A steel spring has a spring constant of 150Nm–1. When a 25 N weight is hung from the spring, it has a stretched length of 55 cm. What was the original length of the spring?
Explanation: By Hooke’s Law F = kx X is the change in length of the spring = Stretched length – Original length 25 = 150(0.55-x) 1/6 = 0.55 – x x = 0.38
346 MCQ for effective preparation of the test of Basics of Physics section.
Read the MCQ statement: A steel spring has a spring constant of 150Nm–1. When a 25 N weight is hung from the spring, it has a stretched length of 55 cm. What was the original .... gth of the spring? , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 17-10484.