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Subject - Physics:

Basics

MCQ - 25-10492

Question:

A cylinder contains 2.46 mol of helium gas at a temperature of 285 K. How much heat must be transferred to the gas to increase its temperature to 602 K if it is heated at constant volume? (The molar specific heat at constant volume, cv, of helium is 12.5 J/mol/K.)

  1. 3426.90 J
  2. 5685.75 J
  3. 8664.21 J
  4. 5685.75 J

Correct Answer: D

Explanation:

Given : n = 2.46 mol , Ti = 285 K , and Tf = 602 K . For the constant-volume process, the work done is zero. Therefore for the Heat Q1 transferred to the gas during the process we have

capture 4 -80170032

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346 MCQ for effective preparation of the test of Basics of Physics section.

Read the MCQ statement: A cylinder contains 2.46 mol of helium gas at a temperature of 285 K. How much heat must be transferred to the gas to increase its temperature to 602 .... is 12.5 J/mol/K.) , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 25-10492.

How to Answer

Solve the question for MCQ No. and decide which option (A through D/E) is the best choice to answer the MCQ, then click/tap the blue button to view the correct answer and it explanation.

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