The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is
Let the numbers be a, b and c. Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131 (a + b + c)2 = a2 + b2 + c2 + 2(ab+bc+ca) (a + b + c)2 = 138 + 2 x 131 = 400 (a+b+c)2 = 400 (a + b + c) = 400 =20.
1297 MCQ for effective preparation of the test of Number System - All NUMBERS on the Tests of Word Problems section.
Read the MCQ statement: The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is , keenly and apply the method you have learn through the video lessons for Number System - All NUMBERS on the Tests to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 44-12811.