Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
Let the age of younger person is x, Then elder person age is (x+16) => 3(x-6) = (x+16-6) [6 years before] => 3x-18 = x+10 => x = 14. So other person age is x + 16 = 30
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
1297 MCQ for effective preparation of the test of Age Problems of Word Problems section.
Read the MCQ statement: Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age , keenly and apply the method you have learn through the video lessons for Age Problems to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 52-12819.