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Practice Adding And Subtracting Rational Expressions How to Multiply And Divide Rational Expressions Multiplying And Dividing Rational Expressions Practice Problems How to Solve a Rational Equation Rational Equations Practice Problems Solving Problems Using Rational Equations Solving Problems Using Rates

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GMAT: How to Add And Subtract Rational Expressions
Multiplying And Dividing Rational Expressions Practice Problems

Let's continue looking at multiplying and dividing rational polynomials. In this lesson, we will look at a couple longer problems, while giving you some practice multiplying and dividing.

Multiplying And Dividing Rational Expressions Practice Problems

Review

Multiplication and division of rational polynomial expressions is easy once you remember the steps.

For multiplication: factor, cancel or slash, and multiply.

For division: factor, flip, cancel or slash, and multiply.

Let's do some larger problems.

Example #1

In example #1, cancel out the like terms to find the solution

((q^2 - 11q + 24) / (q^2 - 18q + 80)) ×((q^2 - 15q + 50) / (q^2 - 9q + 20)) First, we need to factor. (q^2 - 11q + 24) factors into (q - 8)(q - 3). (q^2 - 18q + 80) factors into (q - 10)(q - 8). (q^2 - 15q + 50) factors into (q - 10)(q - 5). (q^2 - 9q + 20) factors into (q - 5)(q - 4).

So, this is what our new expression is going to look like: ((q - 8)(q - 3) / (q - 10)(q - 8)) * ((q - 10)(q - 5) / (q - 5)(q - 4))

Next, we are going to cancel (what I like to call slash) like terms. We're going to cancel or slash (q - 10) over (q - 10), (q - 8) over (q - 8), and finally (q - 5) over (q - 5).

Now that we have canceled or slashed all of the like terms from the top and bottom, we multiply straight across. Don't multiply anything we slashed because those are now 1's. It turns out, our answer is (q - 3) / (q - 4).

Example #2

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In example #2, flip the second fraction before changing the problem to a multiplication one

((y^2 - 9) / (2y + 1)) / ((3 - y) / (2y^2 + 7y + 3))

Let's factor. (y - 9) = (y - 3)(y + 3) and (2y^2 + 7y + 3) = (2y + 1)(y + 3). Our next step is to flip the second fraction and change it to multiplication. Our new expression is going to look like this: ((y - 3)(y + 3) / (2y+ 1)) ×((2y + 1)(y + 3) / ((3 - y)).

The next step is canceling, or what we've been calling slashing. We can slash (2y + 1) over (2y + 1). In the numerator, we have (y - 3)(y + 3) and (y + 3). In the denominator we have (3 - y). If we multiply (3 - y) by -1, we'll get -1(y - 3). Guess what? We can cancel (y- 3) over (y - 3), but remember to leave the -1!

So, our final answer's going to look like: (y + 3)(y + 3) / -1.

But hold on a second! Let's multiply the top and the bottom by -1. This is going to give us -1(y + 3) (y + 3) / 1. When we FOIL, we're going to end up with an answer of -1(y^2 + 6y + 9) / 1. Well if we distribute the -1, we end up with (-y^2 - 6y - 9)!

Example #3

Multiplying by -1 in example #2 removes the negative from the bottom

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We begin by factoring. (x^2 + x - 2) factors into (x + 2)(x - 1), (x^2 - 4x - 12) factors into (x - 6)(x + 2), (x^2 - 9x+ 8) factors into (x - 8)(x - 1), and x^2 - 2x + 1 factors into (x - 1)(x - 1).

Let's start canceling (or slashing)! We can cancel (x - 1) over (x - 1) and (x + 2) over (x + 2). Once we have canceled, or slashed, all of the terms from the top and bottom, we multiply straight across. That gives us a final answer of (x - 8) / (x - 6).